Question

answer please.. .. .. ..​

Answer 1

Observe the figure carefully .

∆ BAC and ∆ EAC lie on the same base AC and

between the same parallels AC and BE.

Therefore, ar(BAC) = ar(EAC) ----- [By Theorem 9.2 (Two triangles on the same base (or equal bases) and between the same parallels are equal in area.)]

So, ar(BAC) + ar(ADC) = ar(EAC) + ar(ADC) ------(Adding same areas on both sides)

or ar(ABCD) = ar(ADE)

Answer 2

Answer:

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