Math, asked by Anonymous, 3 months ago


Answer please!!!!!!!! ​

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Answered by himanshukashyap0719
1

Answer:

taking L.H.S

 \frac{ \sin(x) - 2 { \sin }^{3}(x)  }{2 { \cos}^{3}(x) -  \cos(x )  }  \\  \frac{ \sin(x)(1 - 2 { \sin}^{2}(x))  }{ \cos(x)(2 { \cos }^{2}  (x) - 1)}  \\  \tan(x)  \frac{1 - 2(1 -  { \cos }^{2}(x)) }{2 { \cos}^{2}(x) - 1 }  \\  \tan(x)  \frac{1 - 2 + 2 {cos}^{2}(x) }{2 {cos}^{2}(x) - 1 }  \\  \tan(x)  \frac{2 {cos}^{2} (x) - 1}{2 {cos}^{2} (x) - 1}  \\  \tan(x)

L.H.S = R.H S HENCE PROVE

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