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let us consider a quadrilateral ABCD
two sides are equal AB and Bc = 5.5 cm
let angle b =130°
angle c= 60°
angle d = 50°
let angle a =a
quadrilateral ABCD of sum is 360°
so ,
360= a +b+c+d
360= a+130+60+50
360= a+ 240
a=360-240= 120°
angle A = 120°................
two sides are equal AB and Bc = 5.5 cm
let angle b =130°
angle c= 60°
angle d = 50°
let angle a =a
quadrilateral ABCD of sum is 360°
so ,
360= a +b+c+d
360= a+130+60+50
360= a+ 240
a=360-240= 120°
angle A = 120°................
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