answer please ..........
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x³+2x²-5ax-7/x+1=x²+x-(5a+1) quotient
remainder=5a-6=p
x³+ax²-12x+6/x-2=x²+(a-2)x+2a-16=quotient
q=-4a+38 =remainder
2p+q=6
2(5a-6)-4a+38=6
10a-12-4a+38=6
6a+26=6
6a=-20
a=-20/6=-10/3
remainder=5a-6=p
x³+ax²-12x+6/x-2=x²+(a-2)x+2a-16=quotient
q=-4a+38 =remainder
2p+q=6
2(5a-6)-4a+38=6
10a-12-4a+38=6
6a+26=6
6a=-20
a=-20/6=-10/3
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