Question

❤✨✨ Answer please ✨✨❤​

Answer 1

hey mate!

This gives : 1/p + 1/q = 1/(p+q+x) - 1/x 

=> (q+p) / (pq) = {x - (p+q+x)} / {(p+q+x).x} 

=> (p+q) / (pq) = - (p+q) / {(p+q+x).x} 

=> 1/(pq) = -1 / {(p+q+x).x} ( since, p+q ≠ 0 ) 

=> (p+q+x).x = - pq 

=> px +qx + x^2 + pq = 0 

=> x^2 + px + qx + pq = 0 

=> x ( x + p ) + q ( x + p ) = 0 

=> ( x + p ) . ( x + q ) = 0 

=> x + p = 0 OR x + q = 0 

Answer 2

${\huge {\mathfrak {Answer :-}}}$

➡️ The solution is x = ( - a), ( - b).

Refer above ⬆️ ⬆️..

$<b>$ That's it..