Question

answer please ( 8th question )

Answer 1

Hey!!!...Here is ur answer

If bx^3+3x^2-3 is divided by x-4 then the remainder is R1

So.. b (4)^3+3 (4)^2-3=R1

64b+48-3=R1

64b+45=R1----- eq 1

Now if 2x^3-5x+b is divided by x-4 then the remainder is R2

So.. 2 (4)^3-5 (4)+b=R2

128-20+b=R2

b+108=R2--- eq2

given 2R1-R2=0

So. 2(64b+45)-b-108=0

128b+90-b-108=0

127b-18=0

b=18/127

Hope it will help you

Answer 2

here it is..... . ......