Question

answer please arrgent

Answer 1

answer is in attachment

Answer 2

area =
$\sqrt{3 } \ {a}^{2} \div 4$

$9 \sqrt{3} = \sqrt{3} \times {a}^{2} \div 4 \\ 9 \sqrt{3} \div \sqrt{3} = {a}^{2} \div 4 \\ 9 = {a}^{2} \div 4 \\ 9 \div 4 = {a}^{2} \\ \sqrt{9 \div 4} = \sqrt{ {a}^{2} } \\ 3 \div 2 = a \\ 1.5 = side$