Question

answer please as soon as possible ​

Answer 1

Answer:

50 degree

Step-by-step explanation:

Since bd = cd

The triangle BCD is isoceless ..

So. Angle dbc = dcb = 25 degree

Angle sum property :-

Angle Dbc + dcb + bdc = 180 degree

25 + 25 + bdc = 180

bdc = 130 degree..

Now.. Since abdc is a quadrilateral

Angle bac + angle bdc = 180 degree

bac + 130 = 180

Angle bac = 50 degree.

I cant use symbols..im in pc : (

Answer 2

Step-by-step explanation:

Given,

BC=CD

So,

∆BDC is a isosceles triangle.

Therefore,

angle CBD= angle DCB

So,

angle DCB=25°

Now,

Sum of all angles of a triangle is 180°.

Therefore,

angle B + angle D + angle C =180

25+ angle D +25=180

angle D =180-25-25

angle D = 130°

Sum of opposite angles of the quadrilateral is 180°.

angle BDC + angle BAC =180°

130°+ angle BAC=180°

angle BAC = 180°-130°

angle BAC = 50°

Hope it will be helpful for you.

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