Question

Answer please

Caluculate energy of moles of photond of radiation whose frequency is 5 × 10 power 14 hz

Answer 1

Explanation:

Energy (E) of photons

E = hv

h = 6.626 × 10^-34 js

v = 5 × 10^14 s^-1

E = (6.626 × 10^-34 js) × ( 5 × 10^14 s^-1)

= 3.313 × 10^-19 J

energy of one mole of photond

= (3.313 × 10^-19) × (6.022 × 10^23 mol ^-1)

= 199.51 KJ mol^-1

Answer 2

We know that E = hv

were

E = energy

v = frequency = 5 * 10^14 ( given

h = planks constant= 6.628*10^-34

E = 6.628*5*10^-34*10^14

E = 33.140 * 10^-20