Question

answer please, correct answer would be marked as brainalist

Answer 1

a = 3 , b = 2k , c = 27

if the roots are real and equal , then

$\bf \: b {}^{2} - 4ac = 0$

• (2k)² - 4×3×27 = 0

• 4k² - 324 = 0.

• 4k² = 324

• k² = 81

• k = ± 9

Answer 2

Step-by-step explanation:

$3 {x}^{2} + 2kx + 27 = 0 \\ comparinng \: equation \: with \: \\ a {x}^{2} + bx + c = 0 \\ a = 3 \\ b = 2k \\ c = 27 \\ now \: roots \: are \: equal \: and \: zero \\ so \\ {b}^{2} - 4ac = 0 \\ {(2k)}^{2} - 4 \: (3) \: (27) = 0 \\ 4 {k}^{2} - 4 \times 3 \times 27 = 0 \\ 4 {k}^{2} = 4 \times 3 \times 27 \\ {k}^{2} = 3 \times 27 \\ {k}^{2} = 81 \\ k = - 9 \: \: or \: + 9$