Question

answer please...don't spam please answer properly​

Answer 1

Answer:

1 a

2b

3c

Step-by-step explanation:

Answer 2

$\huge\boxed{Answer}$

Q. (1)

=> aSec²A - atan²A

=> a(Sec²A - tan²A)

=> a(1 + tan²A - tan²A)

=> a * 1

=> a

Q. (2)

=> (1 + tan²A) / (1 + Cot²A)

=> Sec²A/Cosec²A

=> (1/Cos²A)/(1/Sin²A)

=> Sin²A/Cos²A

=> tan²A

Q. (3)

=> Sin2A = 2SinA

=> 2SinA*CosA = 2SinA

=> CosA = 1

=> A = 0