Question

answer please.....factorisation chapter 2 polynomials class 9

Answer 1

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Answer 2

${(3x)}^{3} - ( { \frac{1}{3y}) }^{3} + 3 {(3x)}^{2} ( \frac{ - 1}{3y} ) - 3(3x) { (\frac{1}{3y}) }^{2} \\ compare \: this \: with \: identity \\ {(x - y)}^{3} = {x}^{3} - {y}^{3} + 3 {x}^{2} y - 3x {y}^{2} \\ ( {3x - \frac{1}{3y} )}^{3}$
is the answer