answer please fast it is set 1 class 10
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HERE IS YOUR ANSWER. ....
In triangle ACB
sin30 = BC / 200
BC = 100
CF = 100 -50
CF = 50
Now , In triangle CFD
sin 45 = 50 / CD
CD = 50 root 2
HOPE IT HELPS YOU! ! ! ! !
ALSO FOLLOW ME
In triangle ACB
sin30 = BC / 200
BC = 100
CF = 100 -50
CF = 50
Now , In triangle CFD
sin 45 = 50 / CD
CD = 50 root 2
HOPE IT HELPS YOU! ! ! ! !
ALSO FOLLOW ME
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Anonymous:
hey ghost this figure is % accurate
yeh i know
but i had set 2
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