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Step-by-step explanation:
(a+b+c)^2= a^2+ b^2 + c^2 +2(ab+bc+ca)
p^2= a^2+b^2+c^2+2q
a^2+b^2+v^2= p^2-2q
hope it helps
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Answered by
1
It is p^2 - 2q
Here use the identity (a+b+c)^2= a^2 + b^2 + c^2 + 2(ab + bc + ca)
Putting values,
p^2 = a^2 + b^2 + c^2 + 2q
p^2 - 2q = a^2 + b^2 + c^2
Hope it helps and mark as brainliest
Here use the identity (a+b+c)^2= a^2 + b^2 + c^2 + 2(ab + bc + ca)
Putting values,
p^2 = a^2 + b^2 + c^2 + 2q
p^2 - 2q = a^2 + b^2 + c^2
Hope it helps and mark as brainliest
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