answer please for three also
Answers
Answer:
14.) d) 45°
15.) b) 12cm
16.) 80°
Explanation:
14.) The angle subtended by a chord of a circle at its centre is equal to the angle subtended by the corresponding (minor) arc at the centre.
Angle ADC = 1/2 Angle AOC
90° = 1/2 Angle AOC
45° = Angle AOC
15.)Let AB be a chord of a circle with centre O and radius 13 cm such that AB = 10 cm.
From O, draw OL ⊥ AB. Join OA.
Since, the perpendicular from the centre of a circle to a chord bisects the chord.
∴ AL = LB = ½ AB = 5 cm
Now, in right triangle OLA, we have
OA^2 = OL^2 + AL^2
⇒ 132 = OL^2 = 52
⇒ 132 – 52 = OL^2
⇒ OL^2 = 144
⇒ OL = 12 cm.
Hence, the distance of the chord from the centre is 12 cm.
16.)Given: AB = CD
We know that equal chords of a circle subtend equal angles at the centre.
∴ ∠COD = ∠AOB = 80°
Answer:
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