Question

answer please ............!
Full explanation else report ! ​

Answer 1

Answer:

★First we have to find its another diagonal★

Perimeter of rhombus = 40 cm

side = 1/4 x 40 = 40 cm

One diagonal = 16 cm

Diagonals of rhombus bisect each other at right angles.

OB = $\sqrt{ {ab}^{2} - {oa}^{2} }$

=$\sqrt{ {(10)}^{2} - \: {(8)}^{2} }$

= $\sqrt{100 - 64}$

= $\sqrt{36}$

= 6 cm

Diagonal BD = 6 × 2 = 12 cm

★Now we have to find the area of rhombus★

$\frac{1}{2} \times product \: of \: diagonals$

$\frac{1}{2} \times 12 \times 16$

$= 96 \: {cm}^{2}$

$\huge \red{ \boxed{ (3)96 cm}}$

Answer 2

Explanation:

I think answer is (3) 96 cm

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