Question

Answer please !! Help needed.....

Answer 1

Final Answer : 84g

Steps:
1)
Let the number of moles of CO2 be 'x'.
Then, number of moles of CO will be (1-x).

2)
No. of moles of KOH reacted with CO2 will be 28g/56g =1/2

According to reaction ,
CO2 +2 KOH-----> K2CO3 + H2O

1/x = 2/ (1/2)
=> x = 1/4 .


3) Now, we can say that no. of moles of CO
= 1-x = 3/4 .

Then , after oxidation of all CO to CO2,
New moles of CO2 will be 3/4 , same as CO.

according to reaction ,
No. of moles of KOH = 2 * 3/4 = 3/2 .

3) Mass of KOH required will be 3/2 * 56 = 84g.