Question

answer please

I will mark as braniliest​

Answer 1

$\huge{\bf{\red{AnSwer ~♡~}}}$

Given :-

• AP : a, 3a , 5a, . . . . .

Solution :-

• 1st term = a

• 2nd term = 3a

• Common difference (d) = 2a

$\\ {n}^{th} \: term \: =$

$a_n$ = a + (n - 1)(2a)

• = a + n × (2a) - 2a

Answer 2

Step-by-step explanation:

$\huge\underline{\underline\mathcal\green{ANSWER}} \:$

$\huge{\bf{\underline{\red{See \: Attachment}}}}$