Question

answer please
if your answer will right I mark you as brainliests​

Answer 1

Answer:

Step-by-step explanation:

We will answer this in phase format.

Phase 1 :-

Calculation of perimeter of smaller circles, only the curved portion.

We know that Radius is 1/2 of the diameter of the circle.

Now, what we need to do is apply the formula :-

$\sf{ \pi \times r}$

Here, R will be 28/2 = 14 cm.

$\sf{ \dfrac{22}{7} \times 14}$

This gives us 44 cm.

So, for Circle I and II, perimeter is 44 cm. We need to reduce 28 cm to get only the spherical perimeter because we would be counting the diameter in the bigger circle.

44 - 28 = 16 cm for each circle.

Phase 2 :-

Calculation of perimeter of bigger circle:-

We know the formula :-

$\sf{ \pi \times r}$

In this case the radius is 28 cm.

$\sf{ \dfrac{22}{7} \times 28 }$

This gives us 88 cm.

Now, add the perimeters altogether.

88 + 16 + 16 = 120 cm.

Now, add the straight lines as well!

88 + 16 + 16 + 28 + 28 = 176 cm

= 176 cm is the required perimeter. Hence, the answer.

Answer 2

We will answer this in phase format.

Phase 1 :-

Calculation of perimeter of smaller circles, only the curved portion.

We know that Radius is 1/2 of the diameter of the circle.

Now, what we need to do is apply the formula :-

$\sf{ \pi \times r}$

Here, R will be 28/2 = 14 cm.

$\sf{ \dfrac{22}{7} \times 14}$

This gives us 44 cm.

So, for Circle I and II, perimeter is 44 cm. We need to reduce 28 cm to get only the spherical perimeter because we would be counting the diameter in the bigger circle.

44 - 28 = 16 cm for each circle.

Phase 2 :-

Calculation of perimeter of bigger circle:-

We know the formula :-

$\sf{ \pi \times r}$

In this case the radius is 28 cm.

$\sf{ \dfrac{22}{7} \times 28 }$

This gives us 88 cm.

Now, add the perimeters altogether.

88 + 16 + 16 = 120 cm.

Now, add the straight lines as well!

88 + 16 + 16 + 28 + 28 = 176 cm

= 176 cm is the required perimeter. Hence, the answer.