Question

answer please......
its urgent.............​

Answer 1

Six is a real root of the equations

Answer 2

Answer:

4

Step-by-step explanation:

If a , b can take values 1,2,3,4 . Then the number of the equation of the form ax^{2} + bx + 1 = 0 having real roots .

Solution :

( x+1) ^2

(2x+1)(x+1)

(3x+1)(x+1)

(2x+1)^2