Math, asked by yogitasthore321, 5 months ago

answer please l will mark as brainlist ​

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Answered by Khushimohare62510
0

Answer:

f(x) =k[x^2-(√2+1/3)x+√2/3]

Step-by-step explanation:

f(x)=k[x^2-(sum of it's zeros) x+(product of it's zeros)

zeros are √2 and 1/3

sum of it's zeros=√2+1/3

product of it's zeros=√2×1/3

=√2/3

Now,

f(x) =k[x^2-(sum of it's zeros) x+(product of it's zeros)

f(x) =k[x^2-(√2+1/3)x+√2/3]

where k≠0

Hope it's help u!

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