Question

Answer PLEASE
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Answer 1

Answer:

10a+11b+7c

Step-by-step explanation:

Perimeter of a triangle=sum of all the angles

=(2a+3b+4c)+(5a+6b)+(3a+2b+3c)

=10a+11b+7c

Therefore, perimeter of a triangle=10a+11b+7c

Answer 2

★ As wE knOw ThaT :-

$\large\blue{\boxed{\pink{\underline{\sf{Perimeter \: Of \: a \: Triangle = a + b + c}}}}}$

where a, b and c are the sides of the Triangle.

★ SoLuTioN :-

$\large\sf\rightarrow{Perimeter \: Of \: Triangle }$

$\sf{ = (2a + 3b + 4c) + (5a + 6b) + (3a + 2b + 3c)}$

$\sf{ = 2a + 5a+ 3a + 3b + 6b + 2b + 3c + 4c}$

$\large\sf\red{\underline{ = 10a +11b + 7c}}$

Which is your required answer!!