Math, asked by iqbsayed67, 3 months ago

answer please no wrong otherwise reported that answer ​

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Answered by ij20000005
1

Step-by-step explanation:

LHS = (a-b)(a+b) + (b-c)(b+c) + (c-a)(c+a)

= a(a+b) - b(a+b) + b(b+c) - c(b+c) + c(c+a) - a(c+a)

= a^2 + ab - ab - b^2 + b^2 + bc - bc - c^2 + c^2 + ac - ac- a^2l

= 0

= RHS

by canceling terms

I hope this will help you...

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