Question

Answer please............ please don't give spam answers​

Answer 1

Explanation:

given, t=6s

time of upward motion = 6/2 = 3 s

for upward motion:

time=3s

initial velocity = u m/s

final velocity = 0 m/s

acceleration = -10m/s

so, v= u+at

0 =u - 30

u = 30 m/s

for max. height

S = ut + 1/2 a t ²

S = 90-45

S =45 m

for its position after 4 sec,

S = ut+ 1/2 a (2n-1)

S = 35m

hope it helps:)