English, asked by Anonymous, 9 months ago

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Answered by sansnasare
4

ANSWER

Let the fathers age be x years and his son be y years.

Therefore, seven years ago, age of father = (x-7)

and age of son = (y - 7)

According to the given condition,

x-7 =7(y-7)

or x-7y = -42 ...(1)

After 3 years, fathers age = x+3 and

son's age = (y+3)

As per given condition,

x+3 = 3(y+3)

x-3y = 6 ...(2)

ON subtracting (2) from (1), we get

x - 7y - (x -3y) = -42 - 6

⇒ -4y = -48

⇒ y = 12

On putting value of y in (2), we get

x - 3(12) = 6

⇒ x = 6 + 36 = 42

Hence, present father's age = 42 years

and present son's age = 12 years.

Let the price of one Bat be x and the price of one ball be y,

Now, According to the question,

From(1) we have

By putting different values of x, we get different corresponding values of y.So

X 100 300 -100

Y 600 500 700

Now, From (2), we have,

By putting different values of x, we get different corresponding values of y.So

X 100 400 -200

Y 400 300 500

Let cost each kg of apples = Rs x

Cost of each kg of grapes = Rs y

Given that The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160

So that

2 x + y = 160 … (1)

2x = 160 - y

x = (160 – y)/2

Let y = 0 , 80 and 160 we get

X = (160 – ( 0 ))/2 = 80

X = (160- 80 )/2 = 40

X = (160 – 2* 80 )/2 = 0

X

80

40

0

y

0

80

160

Given that the cost of 4 kg of apples and 2 kg of grapes is Rs 300

so we get

4 x + 2 y = 300 … (2)

Divide by 2 we get

2 x + y = 150

Subtract 2x both side we get

Y = 150 – 2 x

Plug x = 0 , 50 , 100 we get

Y = 150 – 2*0 = 150

Y = 150 – 2* 50 = 50

Y = 150 – 2 * (100 ) = - 50

X

0

50

100

Y

150

50

-50

Algebraic representation

2 x + y = 160 … (1)

4 x + 2 y = 300 … (2)

The cost of 2 kg of apples and 1kg of grapes on a day was found to be Rs 160.

Hope Willl be helpful

Answered by Avanimudabagil
1

Answer:

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Avani R M

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