Question

answer please plz plz​

Answer 1

Answer:

$\huge\underline{\overline{\mid{\bold{\red{Solution:-}}\mid}}}$

$➝ \frac{2x + 1}{3x + 4} = \frac{1}{3}$

By cross multiplication:-

$➝3(2x + 1) = (3x + 4)$

$➝6x + 3 = 3x + 4$

$➝6x - 3x = 3 - 4$

$➝3x = - 1$

$➝x = \frac{ - 1}{3} (Answer)$

• Hope it helps you ✔️✔️

Answer 2

Equation Given:

$\sf{} \dfrac{2x + 1}{3x + 4} = \dfrac{1}{3}$

How to solve such type of questions ?

For this cross multiplication method is used

$: \implies\sf{}3(2x + 1) = 1(3x + 4)$

$: \implies\sf{}6x + 3= 3x + 4$

$: \implies\sf{}6x - 3x= 4 - 3$

$: \implies\sf{}3x= 1$

$: \implies\sf{} \star \boxed{ \tt{}x= \dfrac{1}{3} } \star$

Well you can leave the equation upto here but exactly answer would be

$: \implies\sf{} \star \boxed{ \tt{}x= 0.3334 } \star$

Now let's verify is this value correct or not.

Put value of x in the equation:

$: \implies \sf{} \dfrac{2 ( \frac{1}{3}) + 1}{3( \frac{1}{3}) + 4} = \dfrac{1}{3}$

$: \implies \sf{} \dfrac{ ( \frac{2}{3}) + 1}{( \frac{ \cancel3}{ \cancel3}) + 4} = \dfrac{1}{3}$

$: \implies \dfrac{ \frac{2 + 3}{3} }{4 + 1} = \dfrac{1}{3}$

$: \implies \dfrac{( \frac{5}{3}) }{5} = \dfrac{1}{3}$

$: \implies \dfrac{ \cancel5}{3 \times \cancel5} = \dfrac{1}{3}$

$: \implies\star \boxed{ \dfrac{1}{3} = \dfrac{1}{3}}\star$

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