Answer please
Pramod borrowed rupees 60000 at 12% per annum compounded 50% of the borrowed at the end of first year and 50% of the remaining loan at the end of the second year, find the amount of loan outstanding at the beginning of the third year
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The answer should be 26664
please answer it fast
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Answered by
19
Answer:
26664 which u already said
Step-by-step explanation:
amount borrowed 60000rs
given R=12%
so A=p(1+rt/100)
A=60000(1+12*1/100)
A=67200
given 50% of compounded from principal
50% of 60000=30000 ............(eq-1)
and remove it from amount
67200-30000=37200
and now for second year
A=37200(1+12/100)
A=41664
from question it is said that 50% from remg loan at end of second year
so 50% not from 60000 but from eq-1 that is 30000
which is equal to 15000 is deducted for amount of loan at third year
41664-15000=26664
which is reqd answer
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Answered by
0
Answer:
Hi ✋✋✋
Step-by-step explanation:
here is ur answers
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