Math, asked by Aneesh777, 11 months ago

Answer please

Pramod borrowed rupees 60000 at 12% per annum compounded 50% of the borrowed at the end of first year and 50% of the remaining loan at the end of the second year, find the amount of loan outstanding at the beginning of the third year

Dont copy from web
The answer should be 26664
please answer it fast

Answers

Answered by sunnysinghdollysingh
19

Answer:

26664 which u already said

Step-by-step explanation:

amount borrowed 60000rs

given R=12%

so A=p(1+rt/100)

A=60000(1+12*1/100)

A=67200

given 50% of compounded from principal

50% of 60000=30000         ............(eq-1)

and remove it from amount

67200-30000=37200

and now for second year

A=37200(1+12/100)

A=41664

from question it is said that 50% from remg loan at end of second year

so 50% not from 60000 but from eq-1 that is 30000

which is equal to 15000 is deducted for amount of loan at third year

41664-15000=26664

which is reqd answer

MArk as brainiest if u want to thank me

Answered by kulenurgowdru
0

Answer:

Hi ✋✋✋

Step-by-step explanation:

here is ur answers

Attachments:
Similar questions