Question

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Answer 1

Given Question :-

Find three solutions for the equations 4x + 3y = 24

$\large\underline{\sf{Solution-}}$

Given equation of line is

$\rm :\longmapsto\:4x + 3y = 24$

Substituting 'x = 0' in the given equation, we get

$\rm :\longmapsto\:4 \times 0 + 3y = 24$

$\rm :\longmapsto\:0 + 3y = 24$

$\rm :\longmapsto\:3y = 24$

$\bf\implies \:y = 8$

Substituting 'x = 3' in the given equation, we get

$\rm :\longmapsto\:4 \times 3 + 3y = 24$

$\rm :\longmapsto\:12 + 3y = 24$

$\rm :\longmapsto\:3y = 24 - 12$

$\rm :\longmapsto\:3y = 12$

$\bf\implies \:y = 4$

Substituting 'x = 6' in the given equation, we get

$\rm :\longmapsto\:4 \times 6 + 3y = 24$

$\rm :\longmapsto\:24 + 3y = 24$

$\rm :\longmapsto\:3y = 24 - 24$

$\rm :\longmapsto\:3y = 0$

$\bf\implies \:y = 0$

Hᴇɴᴄᴇ,

➢ Pair of points of the given equation are shown in the below table.

$\begin{gathered}\boxed{\begin{array}{c|c} \bf x & \bf y \\ \frac{\qquad \qquad}{} & \frac{\qquad \qquad}{} \\ \sf 0 & \sf 8 \\ \\ \sf 3 & \sf 4 \\ \\ \sf 6 & \sf 0 \end{array}} \\ \end{gathered}$