Question

Answer please questions number 4​

Answer 1

Answer:

x = 1, 1

Step-by-step explanation:

If $x^{2} + 2x + 1 = 0$, then only x = 1, 1.

$x^{2} + 2x + 1 = 0$

$x^{2}$ - x - x + 1 = 0

x(x - 1) - 1(x - 1) = 0

(x - 1) (x - 1) = 0

x = 1, 1