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HELLO........FRIEND!!
THE ANSWER IS HERE,
Sanika saves 10rupees on 1st day.
Again saves 11rupees on 2nd day.
And saves 12rupees on 3rd day.
So, These savings are in AP.
=> 10,11,12,............
There are 366days in 2016. Because it is a leap year.
So, a=10.
Common difference(d)=11-10 =1.
No. of terms(n) = 366.
The total savings on 31st Dec 2016 ,
=> 70,455
:-)Hope it helps u.
THE ANSWER IS HERE,
Sanika saves 10rupees on 1st day.
Again saves 11rupees on 2nd day.
And saves 12rupees on 3rd day.
So, These savings are in AP.
=> 10,11,12,............
There are 366days in 2016. Because it is a leap year.
So, a=10.
Common difference(d)=11-10 =1.
No. of terms(n) = 366.
The total savings on 31st Dec 2016 ,
=> 70,455
:-)Hope it helps u.
Maharaja111:
thanks a lot
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