Question

Answer please...
Sum of the digits of a 2- digit number is 9.When we interchange the digits, it is found that the resulting new number is greater than the original number by 27. What is the two-digit number?​

Answer 1

Answer:

36

Step-by-step explanation:

Let the digits at tens place and ones place: x and 9−x respectively.

∴ original number =10x+(9−x)

=9x+9

Now Interchange the digits: Digit at ones place and tens place: x and 9−x respectively.

∴ New number: 10(9−x)+x

=90−10x+x

=90−9x

AS per the question

New number = Original number +27

90−9x=9x+9+27

90−9x=9x+36

18x=54

x=

18

54

x=3

Digit at tens place ⇒3 and one's place : 6

∴ Two digit number: 36

Answer 2

Step-by-step explanation:

Let

• One's digit be x
• Ten's digit =9-x

Original number

=10(9-x)+x=90-10x+x=90-9x

Number after interchanging it's digits

=10(x)+9-x=10x+9-x=9x+9

ACQ

9x+9=90-9x+27

18x=126

x=7

One's digit=7

Ten's digit=2

Original number=27