Question

Answer please....
$Evaluate : \int \frac{x + \sqrt{x} }{ \sqrt{x} + 1 } \scriptsize{dx}$
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Answer 1

$\huge\mathcal{\fcolorbox{lime}{black}{\blue{AnsweR:-}}}$

Missing uh toooo Avi

Sabki yaad aa rhi h :(

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$\huge\colorbox{orange}{kнƲşнì❤࿐}$

Answer 2

$\\ \sf \int \frac{x + \sqrt{x} }{ \sqrt{x} + 1} dx$

$\\ = \sf \int \frac{x + \sqrt{x} }{ \sqrt{x} + 1} \times \frac{ \sqrt{x } - 1 }{ \sqrt{x} - 1} dx \: \: \: \: \: \: \: \: \: (x \not = 1)$

$\\ \sf = \int \frac{ \sqrt{x}(x - 1) }{ x - 1} dx$

$\boxed{ \sf \int \frac{x + \sqrt{x} }{ \sqrt{x} + 1} dx = \frac{2x \sqrt{x} }{3} + C} \: \: \: \:, \sf C \in \mathbb{C}$