Math, asked by Anvi2012, 24 days ago

answer please the question....​

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Answered by AmalVerma
1

 \huge{ \green{ \boxed{  \purple{\dag{ \mathfrak{ \orange{ \underline{ \underline{ \blue{answer}}}}}}}}}}

 \rightarrow \frac{(1 +  \sqrt{2}) }{(1 -  \sqrt{2}) }

 \rightarrow  \frac{(1 +  \sqrt{2})(1 +  \sqrt{2} ) }{(1 -  \sqrt{2})(1 +  \sqrt{2} ) }

 \rightarrow  \frac{ {(1 +  \sqrt{2}) }^{2} }{ {(1)}^{2}  -   { (\sqrt{2} )}^{2}  }

 \rightarrow  \frac{1 + 2 \sqrt{2} + 2 }{1 - 2}

 \rightarrow  \frac{3 + 2 \sqrt{2} }{ - 1}

[tex] \rightarrow - (3 + 2 \sqrt{2})

[tex] \rightarrow -3 - 2 \sqrt{2}

Answered by Ananya20170
5

Answer:

3-2√2

Step-by-step explanation:

= 2 - 1

√2 + 1

= 2 - 1 x 2 - 1

√2 + 1 √2 + 1

= 2 - 2 - 2 + 2

(√2 sq - 1 sq)

= 3 - 2 2 (Ans:-)

1

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