Question

answer please this question ​

Answer 1

Answer:

gyan prakash verma

Step-by-step explanation:

$\frac{7^{3}}{ {7}^{x - 2} } = 7^{7} \\ 7^{3} = 7^{7} \times 7^{x + 2}$

then ; 7 is a common factor then 7 is in side....

so ;

$\frac{3}{x - 2} = 7 \\ 3 = 7x - 14 \\ 7x = 14 + 3 \\ 7x = 17 \\ x = \frac{17}{7} = 2 \frac{3}{7} or \: 2.42.$