Math, asked by viyyapuvenkatacharan, 15 days ago

answer please urgent​

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Answers

Answered by amritagurjar01
0

Answer:

Step-by-step explanation:

∫(x+2)√(x-3)dx

Integration by parts

Take (x+2) as a first function & (x-3)^1/2 as a second function

(x+2).1÷2((x-3)^3/2)÷3/2) −∫1. 1÷2 ((x−3)3/2)÷3/2)dx

(1÷2)*2÷3(x+2).(x-3)^3/2 −(2÷3 ) ∗(1÷2)∫(x−3)3/2dx

2 cancel with 2 ..

1÷3(x+2).(x-3)^3/2 −1÷3.((x−3)5/2)÷52+c

Where c is integration constant

Answer

1÷3(x+2).(x-3)^3/2 −2÷15.(x−3)5/2+c

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