answer please urgent
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Step-by-step explanation:
∫(x+2)√(x-3)dx
Integration by parts
Take (x+2) as a first function & (x-3)^1/2 as a second function
(x+2).1÷2((x-3)^3/2)÷3/2) −∫1. 1÷2 ((x−3)3/2)÷3/2)dx
(1÷2)*2÷3(x+2).(x-3)^3/2 −(2÷3 ) ∗(1÷2)∫(x−3)3/2dx
2 cancel with 2 ..
1÷3(x+2).(x-3)^3/2 −1÷3.((x−3)5/2)÷52+c
Where c is integration constant
Answer
1÷3(x+2).(x-3)^3/2 −2÷15.(x−3)5/2+c
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