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1$=60 2$=80 3$=20
Step-by-step explanation:
Let no of 1$ COIN=x
2$=y
5$=z
Total coins=160
ATQ
x=3z
Amount=300
300=2x +3y +5z
300=6z+3y+5z
300=11z + 3y
Second equation
Total coins=X+y+z
160=3z+y+z
160=4z+y
Solving both eq by elimination method
-20=-1z
Z=20
X=60
Y=80
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