Question

Answer please we are very confused by this problem

Answer 1

Total angles of quadrilateral is 360

let the difference be d

<A=100-2d

<B=100-d

<C=100

<D=100+d

as A+B+C+D=360

=> 400-2d=360

=> d=20

=>

A=60

B=80

C=100

D=120