Question

Answer please....
With process..
Three consecutive integers add up to 51. What are these integers?​

Answer 1

Answer:

let the numbers be a-d ,a ,a+d

By given condition

a-d+a+a+d=51

3a =51

a=51/3

a=17

Answer 2

Given : The sum of three consecutive integers is 51.

To find : The consecutive integers.

$\qquad$_______________

According to the question, let :

$\qquad$ ❍ First integer = $\sf x$

$\qquad$ ❍ Second integer = $\sf x+1$

$\qquad$ ❍ Third integer = $\sf x+2$

We are given that their results 51, so we get an equation as follows :

$\sf \qquad \dashrightarrow \: x + (x + 1) + (x + 2) = 51$

$\sf \qquad \dashrightarrow \: x + x + x + 1 + 2 = 51$

$\sf \qquad \dashrightarrow \: 3x + 3 = 51$

$\sf \qquad \dashrightarrow \: 3x = 51 - 3$

$\sf \qquad \dashrightarrow \: 3x = 48$

$\sf \qquad \dashrightarrow \: x = \cancel{\dfrac{48}{3} }$

$\sf\qquad \dashrightarrow \: x = 16$

So, the number is 16.

$\qquad$_______________

Finding the numbers :

We shall find the numbers by substituting them :

$\qquad$❍ First number : x = 16

$\qquad$❍ Second number : x+1 = 17

$\qquad$❍ Third number : x+2 = 18