Question

answer pleasee pleasere​

Answer 1

AREA OF SQUARE WHOSE DIAGONAL IS 12 CM

Answer 2

Step-by-step explanation:

We will divide the Square into two equal right angled isosceles triangles..

W.K.T.

$side {}^{2} + side {}^{2} = diagonal {}^{2}$

$x {}^{2} + x {}^{2} = 12 {}^{2}$

$2x {}^{2} = 144$

$x = 144 \div 2 \\ = 72$

$therefore \: side = \sqrt{72}$

As side = √72

We know that area of square

$= side {}^{2}$

$= > | \sqrt{72} | {}^{2}$

$= > 72 cm {}^{2}$

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