Question

answer pleaseeeeeeeeeeeeeeeeeee Q. 38​

Answer 1

Step-by-step explanation:

Given:

In a triangle ABC,AB is the median dawn from A to B

To Prove :AB+AC>AD

Construction: produce AD to D so that DE = ,join BE.

proof:

Now in ◇ADC and ◇EDB.

AD=DE (by const)

DC=BD ( as D is mid point)

◇ADC=◇EDB ( vertically opposite ◇ s)

therefore,

In ◇ ABE, ◇ ADC ~◇EDB(by SAS)

This gives, BE= A

AB+BE>AE

AB+AC>2AD (•: AD=DE and BE=AC)

is greater than the the median drawn to the third side.......

Hence the some of any two sides of a triangle