Question

Answer pls.........
13 question

Answer 1

Answer:

we know that,

TSA of the solid=TSA of cone+TSA of cylinder +base area

$tsa \: of \: the \: solid = \pi \: rl + 2\pi \: rh + \pi \: {r}^{2} \\ tsa \: of \: the \: solid = \pi \: r(l + 2h + r) {units}^{2}$

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Hope it helps you.....