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Answer:
x^3+8y^3
Step-by-step explanation:
(a+b)(a2−ab+b2)=a3+b3
Here, we can solve the question as follows:
(x+2y)(x^2-2xy+4y^2)
=(x+2y)(x^2-(x)(2y)+(2y)^2)
=(x)^3+(2y)^3
=x^3+8y^3
(x+2y)(x2−2xy+4y2)=(x+2y)(x2−(x)(2y)+(2y)2)=(x)3+(2y)3=x3+8y3
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Hope it helps
Answered by
0
I am giving the ans
(x+2y)(x²-2xy+4y²)
=> (x+2y) (x²-(x)(2y)+ (2y²) )
we know that
(a+b) (a²-b²-ab)
= a³+ b³
=> x³ +(2y³)
=> x³+ 8y³
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