Question

answer pls (class 10 question)​

Answer 1

GiveN :-

• In ∆ABC , ∠ A is obtuse angle .
• PB $\perp$ AB .
• QC $\perp$ BQ .

To ProvE :-

• AB/AP = AC/AQ .

ProoF :-

We will use similarity of triangles to Prove the above . So ,

In ∆ APB and ∆AQC ,

• ∠APB = ∠AQC = 90° [ given ]
• ∠PAB = ∠QAC [ vertically opposite angles]

Hence by AA similarity Condition , ∆ APB ~ ∆AQC . So , we can say that ,

$\large\red{\sf \implies \dfrac{AB}{AP}=\dfrac{AC}{AQ}}$

[ Since corresponding parts of similar triangle are proportional. ]

$\Large{\boxed{\pink{\sf Hence\:\:Proved\:\:!}}}$