Math, asked by ghostrider117, 4 months ago

Answer pls I will mark as Brainliest For Fast Answer​

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Answered by amitsharma777222999
0

Answer:

Px/(b-c)=Qy/(c-a)=Rz/(a-b)=k

Px=k(b-c)

Qy=k(c-a)

Rz=k(a-b)

Pax+Qby+Rcz=ak(b-c)+bk(c-a)+ck(a-b)

=k(ab-ac+bc-ba+ca-cb)

=k*0=0

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