Answer pls I will mark as Brainliest For Fast Answer
Attachments:
Answers
Answered by
0
Answer:
Px/(b-c)=Qy/(c-a)=Rz/(a-b)=k
Px=k(b-c)
Qy=k(c-a)
Rz=k(a-b)
Pax+Qby+Rcz=ak(b-c)+bk(c-a)+ck(a-b)
=k(ab-ac+bc-ba+ca-cb)
=k*0=0
Similar questions