Question

answer pls .... quickly​

Answer 1

Answer:

done

Step-by-step explanation:

Our aim is to prove that PM = 2RM.

From the question we have that length of PQ is equal to the double length of RS, then we have:

 ⇒ PQ = 2RS

Now considering the triangle ΔPMQ and triangle ΔRMS, we can conclude that:

∠MPQ = ∠MRS (alternate angles)

∠MQR = ∠MSR (alternate angles)

We know can conclude that the triangle ΔPMQ are congruent with triangle ΔRMS (ΔPMQ ≅ ΔRMS), then we can conclude that:

⇒ pq/sr = pm/rm=qm/sm

⇔ 2RM = PM ⇒ 2SM =qm