Math, asked by irfanmayufcvn8a, 7 months ago

Answer pls
Very fast plzzzz

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Answers

Answered by jayant6096
1

6^-5 x 6^2n+1=6^13÷6^7

6^2n-4=16^13/7

Now compairing powers,

2n-4=13/7

14n-28=13

14n=41

n=41/14

Answered by spacelover123
6

Question

\sf 6^{-5}\times 6^{2n+1}=6^{13}\div 6^7

Answer

Step 1: Find the value of RHS. Use this law to do so ⇒ \sf a^{m}\div a^{n} =a^{m-n}

\sf 6^{-5}\times 6^{2n+1}=6^{13}\div 6^7

\sf 6^{-5}\times 6^{2n+1}=6^{13-7}

\sf 6^{-5}\times 6^{2n+1}=6^{6}

\rule{300}{0.5}

Step 2: Since the base of all the numbers is '6' we will form an equation with all the exponents.

We have to use this law too ⇒ \sf a^{m} \times a^{n}=a^{m+n}

Our equation would be ⇒ \sf  -5+(2n+1) = 6

Let's solve your equation step-by-step.

\sf  -5+(2n+1) = 6

Step 1: Simplify both sides of the equation.

\sf  -5+2n+1 = 6

(Combine Like Terms)

\sf  (2n)+(-5+1)=6

\sf  2n+-4=6

\sf  2n-4=6

Step 2: Add 4 to both sides.

\sf  2n-4+4=6+4

\sf  2n=10

Step 3: Divide both sides by 2.

\sf  \frac{2n}{2}=\frac{10}{2}

\sf n= 5

Verification if n = 5

\sf  -5+(2n+1) = 6

\sf  -5+[(2\times 5) +1 ]= 6

\sf  -5+[10 +1 ]= 6

\sf  -5+11= 6

\sf  6=6

\rule{300}{0.5}

∴ n = 5 in the equation ⇒  \sf \bf   6^{-5}\times 6^{2n+1}=6^{13}\div 6^7

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