Question

ANswER PLz..‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️‼️​

Answer 1

Answer: (c) 410.67 sq. cm

Solution:

Area of smaller circle

$\tt{\pi r^{2} = 49\pi}$ sq. cm

Area of bigger circle

$\tt{\pi r^{2} = 196\pi}$ sq. cm

Area of sector of bigger circle

$\tt{\frac{A}{360} \pi r^{2} = \frac{40}{360} \times 196 \pi = \frac{196\pi}{9}}$

Area of sector of smaller circle

$\tt{\frac{A}{360} \pi r^{2} = \frac{40}{360} \times 49 \pi = \frac{49\pi}{9}}$

Area of shaded region

$\tt{196\pi - 49\pi - \frac{196\pi}{9} + \frac{49\pi}{9}}$

=> 1232/3 = 410.67 sq. cm

Answer 2

Answer:

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It's right answer

(c) 410.67 sq. cm

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