answer plz.................................. 4 ....number question
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Let alpha = a and beta = b
Now , 1/a+1/b:-
1/a+1/b
=a+b/ab (Taking LCM)............ equation 1
Now the polynomial=5y^2-7y+1
So , a+b = - coefficient of y/ coefficient of y^2
=-(-7)/5
=7/5
Now , ab= constant term / coefficient of y^2
=1/5
Now substituting ab and a+b in equation 1 :-
a+b/ab
=(7/5)/(1/5)
=7
Answer :- Here 1/a+1/b=7
If you find it helpful please mark it as brainliest....
Now , 1/a+1/b:-
1/a+1/b
=a+b/ab (Taking LCM)............ equation 1
Now the polynomial=5y^2-7y+1
So , a+b = - coefficient of y/ coefficient of y^2
=-(-7)/5
=7/5
Now , ab= constant term / coefficient of y^2
=1/5
Now substituting ab and a+b in equation 1 :-
a+b/ab
=(7/5)/(1/5)
=7
Answer :- Here 1/a+1/b=7
If you find it helpful please mark it as brainliest....
Pratibhadeep:
I'll when someone else .........................will answer
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