Question

answer plz ?????????​

Answer 1

Step-by-step explanation:

We have,

$\tt{x(x - y) = 8y - 7}$

$\sf{ \implies \: x^{2} - xy = 8y - 7}$

$\sf{ \implies \: x^{2} - xy - (8y - 7) = 0}$

$\sf{ \implies \: x = \dfrac{y \pm \sqrt{ {y}^{2} + 4(8y - 7) }}{2}}$

$\sf{ \implies \: x = \dfrac{y \pm \sqrt{ {y}^{2} + 32y -28 }}{2}}$

Since, x is an integer, so,

$\sf{y^2+32y-28=0}$,

So,

$\sf{ \implies \: x = \dfrac{y}{2}}$

$\sf{ \implies \: \dfrac{x}{y} = \dfrac{1}{2}}$

$\sf{ \implies \: \dfrac{x + y}{x - y} = \dfrac{1 + 2}{1 - 2}}$

$\sf{ \implies \: \dfrac{x + y}{x - y} = - 3}$