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Nucleus is initially stationary, so its speed is zero. Its momentum (p = mv) is also zero initially.
The nucleus contains an amount of A nucleons.
Nucleus decays by emitting proton with speed v to form new nucleus with speed u.
Number of nucleons in new nucleus = A – 1
Let the mass of 1 nucleon = m
After decay,
Momentum of proton = mv {the proton is a nucleon}
Momentum of new nucleus = (A – 1)m(–u)
{negative is taken for the speed because the new nucleus and the proton travel in opposite direction. The direction of motion of the proton is taken as positive [v is taken as positive], so u should be taken as negative.}
Total momentum after decay = mv – (A – 1)mu
From the conservation of momentum,
Sum of momentum before decay=sum of momentum after decay
0 = mv – (A – 1)mu
v = (A – 1)u
The nucleus contains an amount of A nucleons.
Nucleus decays by emitting proton with speed v to form new nucleus with speed u.
Number of nucleons in new nucleus = A – 1
Let the mass of 1 nucleon = m
After decay,
Momentum of proton = mv {the proton is a nucleon}
Momentum of new nucleus = (A – 1)m(–u)
{negative is taken for the speed because the new nucleus and the proton travel in opposite direction. The direction of motion of the proton is taken as positive [v is taken as positive], so u should be taken as negative.}
Total momentum after decay = mv – (A – 1)mu
From the conservation of momentum,
Sum of momentum before decay=sum of momentum after decay
0 = mv – (A – 1)mu
v = (A – 1)u
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